In Java, we can use for loop, while loop or do-while loops to print different number, alphabet or star patterns programs.
Here are some examples for character or letter pattern programs. For other patterns, please refer the links at the end of the post.
Character Pattern Program 1:
A
BC
DEF
GHIJ
KLMNO
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | class CharPattern1 { public static void main(String[] args) { char ch = 'A'; for (int i = 1; i <= 5; i++) { for (int j = 1; j <= i; j++) { System.out.print(ch); ch++; } System.out.println(); } } } |
Character Pattern Program 2:
Enter a String:
LOTUS
L
LO
LOT
LOTU
LOTUS
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | import java.util.Scanner; public class CharPattern2 { public static void main(String[] args) { System.out.println("Enter a String: "); Scanner sc = new Scanner(System.in); String s = sc.nextLine(); sc.close(); char [] a=s.toCharArray(); for (int i = 0; i < a.length; i++) { for (int j = 0; j <= i; j++) { System.out.print(a[j]); } System.out.println(); } } } |
Character Pattern Program 3 : Diamond shape composed of Letters
Enter a Char between A to Z : G
A
B B
C C
D D
E E
F F
G G
F F
E E
D D
C C
B B
A
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 | package com.topjavatutorial; import java.util.Scanner; public class DiamondPattern { public static void main(String[] args) { char[] letter = { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z' }; int letter_number = 0; // array of strings String[] diamond = new String[26]; // get the letter System.out.print("Enter a Char between A to Z : "); Scanner reader = new Scanner(System.in); try { char user_letter = reader.next("[A-Z]").charAt(0); // search for letter number in the array letter for (int i = 0; i < letter.length; i++) { if (letter[i] == user_letter) { letter_number = i; break; } } // construct diamond for (int i = 0; i <= letter_number; i++) { diamond[i] = ""; // add initial spaces for (int j = 0; j < letter_number - i; j++) { diamond[i] += " "; } // add letter (first time) diamond[i] += letter[i]; // add space between letters if (letter[i] != 'A') { for (int j = 0; j < 2 * i - 1; j++) { diamond[i] += " "; } // add letter (second time) diamond[i] += letter[i]; } // Draw the first part of the diamond as it's composing. System.out.println(diamond[i]); } for (int i = letter_number - 1; i >= 0; i--) { // Draw the second part of the diamond // Writing the diamondArray in reverse order. System.out.println(diamond[i]); } } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } finally { reader.close(); } } } |
Character Pattern Program 4:
Enter a String:
APPLE
A
AP
APP
APPL
APPLE
APPL
APP
AP
A
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 | import java.util.Scanner; public class CharPattern4 { public static void main(String[] args) { System.out.println("Enter a String: "); Scanner sc = new Scanner(System.in); String s = sc.nextLine(); sc.close(); int length = s.length(); char[] a = s.toCharArray(); for (int i = 0; i < length; i++) { for (int j = 0; j < i; j++) System.out.print(a[j]); System.out.println(); } for (int i = length; i >= 0; i--) { for (int j = 0; j < i; j++) System.out.print(a[j]); System.out.println(); } } } |
Character Pattern Program 5:
Enter a String:
HELLO
Printing the pattern:
HELLO
HELL
HEL
HE
H
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | import java.util.Scanner; public class CharPattern { public static void main(String[] args) { System.out.println("Enter a String: "); Scanner sc = new Scanner(System.in); String s = sc.nextLine(); sc.close(); int length= s.length(); char [] a=s.toCharArray(); System.out.println("\nPrinting the pattern: "); for (int i = length-1; i >= 0; i--) { for (int j = 0; j <= i; j++) { System.out.print(a[j]); } System.out.println(); } } } |
Character Pattern Program 6:
A
BBB
CCCCC
DDDDDDD
EEEEEEEEE
FFFFFFFFFFF
GGGGGGGGGGGGG
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | public class CharPattern { public static void main(String[] args) { char ch = 'A'; int number = 7; int count = number - 1; for (int k = 1; k <= number; k++) { for (int i = 1; i <= count; i++) System.out.print(" "); count--; for (int i = 1; i <= 2*k-1; i++) System.out.print(ch); System.out.println(); ch++; } } } |
Character Pattern Program 7:
A
BBB
CCCCC
DDDDDDD
EEEEEEEEE
DDDDDDD
CCCCC
BBB
A
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | public class CharPattern7 { public static void main(String[] args) { char ch = 'A'; int number = 5; int count = number - 1; for (int k = 1; k <= number; k++) { for (int i = 1; i <= count; i++) System.out.print(" "); count--; for (int i = 1; i <= 2 * k - 1; i++) System.out.print(ch); System.out.println(); ch++; } count = 1; ch--; for (int k = 1; k <= number - 1; k++) { for (int i = 1; i <= count; i++) System.out.print(" "); count++; ch--; for (int i = 1; i <= 2 * (number - k) - 1; i++) System.out.print(ch); System.out.println(); } } } |
Character Pattern Program 8:
A
BB
CCC
DDDD
EEEEE
FFFFFF
GGGGGGG
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | public class CharPattern8 { public static void main(String[] args) { char ch = 'A'; int number = 7; int count = number - 1; for (int k = 1; k <= number; k++) { for (int i = 1; i <= count; i++) System.out.print(" "); count--; for (int i = 1; i <= k; i++) System.out.print(ch); System.out.println(); ch++; } } } |
N.B.
We are still adding more letter/character pattern programs to this article. If you would like to see any other programs, please add in the comments section and we will be happy to add them here.
Also, here are some of the other pattern programs you may like:
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I am a complete beginner in programming and I am having difficulties to solve this problem.
Each letter is converted to the letter which
is 3 places after it in the alphabets. For example, A is converted to D.
The sequence is cyclic, that is, X is converted to A, Y to B and Z to C.
Write a java program that allows you to input a line of text and
outputs the encrypted version. The line of text is terminated by a ‘.’.
This is what I got so far:
import java.util.scanner
public class ReplaceString {
public static void main(String[] args) {
string str=”Meet me at Times Square tonight.”
System.out.println(str replace (all letters by the fourth letter found after it in alphabetical order,
a=d,
b=e,
c=f,
d=g,
e=h,
f=i,
g=j,))
// loop till alphabetical cycle is complete.
}
}
phhw ph dw wlphv vtxdvh wrqljkw
please help
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